Question

find the value of x³ + y³ + Z³- 3xyz if X + Y + Z=12 and X² + Y² + Z²= 70​

Answer 1

Step-by-step explanation:

given: x+y+z=12

x²+y²+z²=70

x³+y³+z³-3xyz =(x+y+z)(x²+y²+z²-xy-yz-xz)

=12(70-xy-yz-xz)

(x+y+z)²=x²+y²+z²+2xy+2yz+2xz

12²=70+2(xy+yz+xz)

xy+yz+xz=37

use identity