Find the value of (xb-c)b+c-a(xc-a)c+a-b(xa-b)a+b-c
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Answer:
(xa+b)a-b .(xb+c)b-c. (xc+a)c-a
= x(a+b)(a-b). x(b+c)(b-c) .x(c+a)(c-a)
= x0
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