Question

find the value of Xfind the value of x square + 1 upon x square if x is equal to 3 + 5 root 6​

Answer 1

$x {}^{2} + \frac{1}{x {}^{2} } \\ the \: value \: given \: is \: \: \: x = 3 + 5 \sqrt{6} \\ now \: we \: put \: the \: value \: of \: x \: in \: quation \: \\ (3 + 5 \sqrt{6} ) {}^{2} + \frac{1}{(3 + 5 \sqrt{6}) {}^{2} } \\ (9 + 150 + 30 \sqrt{6} ) + \frac{1}{(9 + 150 + 30 \sqrt{6} )} \\ (159 + 30 \sqrt{6} ) + \frac{1}{(159 + 30 \sqrt{6} )} \\ now \: we \: take \: \: lcm \: of \: the \: eqation \: \\ \frac{(159 + 30 \sqrt{6})(159 + 30 \sqrt{6} ) + 1}{159 + 30 \sqrt{6} } \\ \frac{25281 + 4770 \sqrt{6} + 4770 \sqrt{6} + 5400 + 1}{159 +30 \sqrt{6}} \\ \frac{30682 + 9540 \sqrt{6} }{159 + 30 \sqrt{6} } \\ > \frac{30682 + 9540 \sqrt{6} }{159 + 30 \sqrt{6} } \: \: \: \: \: \: \: its \: your \: answer \: i \: hope \: that \: helps \: you \:$