Math, asked by joseph8307, 5 months ago

Find the value of (Xyz) Square when the vaule of x is 3 ,y is 2 and z is 1

Answers

Answered by rangilidoley
2

Answer:

The value is 36.

Step-by-step explanation:

Given,

x = 3

y = 2

z = 1

•°• (xyz)^2 = ( 3*2*1 )^2

= 6^2

=36

Answered by rkmadani64
1

Answer:

36

Step-by-step explanation:

I think the answer is 36.

x= 3

y= 2

z= 1

So, here it's given that we have to find the value of xyz

(x)2 × (y)2 × (z)2

(3)2 × (2)2 × (1)2

(9) × (4) × (1)

= 36

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