Math, asked by archnadhillon7, 17 days ago

find the value of y [(1/3)^5×(1/3)^3]=(1/3)^3y-5​

Answers

Answered by rohitraout53
2

Answer:

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Answered by krishpmlak
0

Answer:

Step-by-step explanation:

GGiven that,

[ (1/3)^5 × ( 1/3 )^3 ] = ( 1/3 )^ 3y- 5

( 1/3 ) ^ 5+3 = ( 1/3 )^ 3y - 5 (∵Bases are equal then powers should be add )

( 1/3 ) ^8 = ( 1/3 )^3y- 5

8 = 3y - 5 ( ∵ Bases are equal, then powers should be equal. )

8 + 5 = 3y

13 = 3y

13/3 =y

∴ y = 13/3 is the answer.

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