find the value of y [(1/3)^5×(1/3)^3]=(1/3)^3y-5
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Step-by-step explanation:
GGiven that,
[ (1/3)^5 × ( 1/3 )^3 ] = ( 1/3 )^ 3y- 5
( 1/3 ) ^ 5+3 = ( 1/3 )^ 3y - 5 (∵Bases are equal then powers should be add )
( 1/3 ) ^8 = ( 1/3 )^3y- 5
8 = 3y - 5 ( ∵ Bases are equal, then powers should be equal. )
8 + 5 = 3y
13 = 3y
13/3 =y
∴ y = 13/3 is the answer.
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