Math, asked by harinidevaraj1901, 10 hours ago

find the value of y(1) by solving the differential equation y dy/dx=6x²+5,y(0)=2

Answers

Answered by iamironmans252

0

Answer:

dy=(6x^2+5)dx

y=2x^3+5x+c

y(0)=2 gives c=2

therefore y=2x^3+5x+2

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