Math, asked by piyushssngh, 11 months ago

Find the value of y

12y + 40y + 17 = 0

Answers

Answered by Anonymous
106

Answer :-

12y + 40y + 17 = 0

=> 52y + 17 = 0

=> 52y = -17

=> y = -17/52

Verification :-

Take L.H.S. ;

Put the value of y ;

=> 12 (-17/52) + 40 (-17/52) + 17

=> -204/52 - 680/52 + 17

=> (-204 - 680 + 884)/52

=> -804 + 804 / 52

=> 0/52 = 0 = R.H.S.

Hence, The Value of y is -17/52.

Answered by BoyBrainly
4

 \bold{ \large{ \underline{ Given \:  \:  \: }}}

 \to \:  \bold{12y + 40y + 17 = 0 \: }

 \bold{ \underline{ \large{  To \:  Find \: \:  \:  }}}

 \to \:  \bold{Value  \: Of \:  y \: }

  \underline{\bold{ \large{  Solution  \:  \: \:  }}}

  \to\bold{12y + 40y + 17 = 0} \\ \\  \to </p><p> \bold{52y + 17 = 0} \\ \\   \to</p><p> \bold{ y =  \frac{ - 17}{52}  }  \\  \\ \to \bold{ y = - \:  0.32}

Hence , The Value of y Is - 0.32

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