Question

find the value of (y^2+2y-3)÷(y-1)​

Answer 1

$(y^2+2y-3)÷(y-1)$

Answer 2

Step-by-step explanation:

$(y^2+2y-3 )÷(y-1) \\ = \frac{y^2+2y-3}{y - 1} \\ = \frac{ {y}^{2} + (3 - 1)y - 3}{y - 1} \\ = \frac{ {y}^{2} + 3y - y - 3 }{y - 1} \\ = \frac{ y(y + 3) - 1(y + 3) }{y - 1} \\ = \frac{(y - 1)(y + 3)}{(y - 1)} \\ = y + 3$

Middle factor of the numerator or upper part,

Hope it helps,,,