find the value of y ²-x when?
Answers
Answered by
0
Step-by-step explanation:
Given,
(i)
(2+3i)x
2
−(3−2i)y=2x−3y+5i
(2x
2
−3y)+(3x
2
+2y)i=2x−3y+5i
[
2x
2
−3y=2x−3y
3x
2
+2y=5
]
solving the above 2 equations, we get,
[
2x
2
−3y=2x−3y
3x
2
+2y=5
]⇒(
x=0,
x=1,
y=
2
5
y=1
)
(ii)
4x
2
+3xy+(2xy−3x
2
)i=4y
2
−
2
x
2
+(3xy−2y
2
)i
8x
2
+6xy+2i(2xy−3x
2
)=8y
2
−x
2
+2i(3xy−2y
2
)
[
8x
2
+6xy=8y
2
−x
2
4xy−6x
2
=6xy−4y
2
]
solving the above 2 quadratic equations, we get,
[
8x
2
+6xy=8y
2
−x
2
4xy−6x
2
=6xy−4y
2
]⇒(
y=0,
x=0
)
Answered By
toppr
Answered by
4
x+y=2 , x²+y²=2. X=2-y(put this in eqn 2 ). (2–y)²+y²=2. 4+y²-4y+y²=2. 2y²-4y+2. 2(y²-2y +1). Y²-1y-1y+1. Y(y-1)-1(y-1). Y-1=0. Y=1.
ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘꜱ ʏᴏᴜ.
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