Math, asked by amritharajesh1, 8 months ago

Find the value of y -3/√2y-√8y=0 (Pls show the calculation step by step)

Answers

Answered by vaishnavi2214
1

Answer:

y - 3 \sqrt{2} y -  \sqrt{8} y = 0 \\ y - 3 \sqrt{2}y - 2 \sqrt{2}  y = 0 \\ y - 5 \sqrt{2}y = 0 \\ y(1 - 5 \sqrt{2}  ) = 0 \\ y = 0

Answered by virendersingh89
0

y =3

y-3/2y -8y = 0

y-3/y(2- 22) = 0

y-3/y(-2 ) =0

y-3 =0

y=3

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