Find the value of y
3
(a) y X
= 1
22
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If y = 2^x+1, what is the value of y – x?
(1) 2^2x+2 = 64
(2) y = 2^2x –1
1) 2^2x+2=2^6
2x+2=6
x=2
2^x+1-2^1 => x+1-1=0 ==> x=0
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