Question

find the value of Y for which line segment between the points p (2,-3) and Q (10,y) is 10 units​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

x1=2 y1=-3 x2=10 y2=y

l=10 units

l^2=(x2-x1)^2-(y2-y1)^2

10^2=(10-2)^2+(y-(-3))^2

100=64+(y-(-3))^2

100-64=(y+3)^2

36=(y+3)^2

taking square roots on both sides

CASE 1

6=y+3

thus, y=6-3=3

CASE 2

-6=y+3

thus y=-6-3=-9