Question

find the value of y for which the distance between the points p(2,-3)and q(10,y) is 10units​

Answer 1

Answer:

y=3 (or)-9

Step-by-step explanation:

the distance is

^(10-2)^+(y+3)^=10

squaring in both sides we get

8^+(y+3)^=100

64+(y+3)^=100

y+3^=36

y+3=+-6

if we take-6

y=-6-3

y=-9

and

if we take+6

y=+6-3

y=+3