Question

Find the value of y for which the distance between the points p(2,-3) and q(10,y) is 10 units

Answer 1

Answer:

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Answer 2

||✪✪ QUESTION ✪✪||

Find the value of y for which the distance between the points p(2,-3) and q(10,y) is 10 units ?

|| ✰✰ ANSWER ✰✰ ||

Distance b/w two points (x1,y1) and (x2,y2) is given by :-

D = √(x2-x1)² + (y2-y1)²

From given values we have,

=> D = 10 units

=> x1 = 2 ,

=> y1 = (-3)

=> x2 = 10

=> y2 = y

Putting all values in Formula now we get,

→ 10 = √10-2)² + (y-(-3))²

Squaring both sides, we get,

→ 100 = 64 + y² + 9 +6y

→ y² +6y - 27 = 0

Splitting the middle term now,

→ y²+ 9y -3y -27 = 0

→ y(y+9) -3(y+9) = 0

→ (y+9)(y-3) = 0

putting both Equal to zero now, we get,

→ y = (-9) or 3 .

Hence, value of y will be (-9) or 3.

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