Question

. Find the value of Y for which the distance between the points P(2, -3) and Q( 10, y) is 10 units.

Answer 1

Answer:

Step-by-step explanation:

distance=(sqrt((x2-x1))^2+(y2-y1)^2)

given d=10

sqrt((y+3)^2+(8^2))=10

y^2+9+6y+64=100

y^2+6y=100-64-9=36-9=27

y^2+6y-27=0

y^2+9y-3y-27=0

y(y+9)-3(y+9)=0

y=-9,3

Answer 2

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