Question

find the value of y for which the distance between the points p(-5,y) and q(-1,3) is 4√2 units?​

Answer 1

Step-by-step explanation:

use distance formula and square both sides then u will get

4²+(3-y)²=(4√2)²

(3-y)²=32-16

9-6y+y²=16

y²-6y-7=0

y²-7y+y-7=0

(y+1)(y-7)=0

y= 7 & -1 answer

Answer 2

Answer:

answer to your question is above