find the value of y for which
the distance
between the points
p(2,-3) and
8 (10,4) is
10 units
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6
Answer:
Hello.
the formula to calculate the distance between two points (a,b) and (c,d) is given by
dist d = √(a-c)² + (b-d)²
applying it for this ques we have d=10 units
10 = √(2 - 10)² + (-3-y)²
squaring both sides
100 = (-8)² + (9 + y² + 6y)
100 = 64 +9 + y² + 6y
y² + 6y - 27 = 0
y² + 9y - 3y - 27 = 0
y(y + 9) -3(y + 9) = 0
(y-3)(y+9) = 0
y=3 or y=-9
both values of y are possible unless no other condition is specified in the question.
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