Question

find the value of y for which the distance between the points P(2,-3) and Q(10,y) is 10 unites

Answer 1

Answer:

Explanation:

hello.

the formula to calculate the distance between two points (a,b) and (c,d) is given by

dist d = √(a-c)² + (b-d)²

applying it for this ques we have d=10 units

10 = √(2 - 10)² + (-3-y)²

squaring both sides

100 = (-8)² + (9 + y² + 6y)

100 = 64 +9 + y² + 6y

y² + 6y - 27 = 0

y² + 9y - 3y - 27 = 0

y(y + 9) -3(y + 9) = 0

(y-3)(y+9) = 0

y=3 or y=-9

both values of y are possible unless no other condition is specified in the question.

hope it helps