find the value of y for which the distance between the points A(2,3) and B(-1,y) is 5.
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Step-by-step explanation:
Given: Points A(2,−3),B(10,y) and AB=10
Distance formula: AB=(x2−x1)2+(y2−y1)2
AB2=(x2−x1)2+(y2−y1)2
(10)2=(10−2)2+(y+3)2
100=(8)2+y2+6y+9
y2+6y+9+64=100
y2+6y+73−100=0
y2+6y−27=0
y2+9y−3y−27=0
y(y+9)−3(y+9)=0
(y+9)(y−3)=
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