find the value of y for which the distance between the points P(2,-3)and Q(10,y) is 10 units
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16
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misskritimishra:
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Answered by
12
Answer9,-3
Step-by-step explanation:
By distance formula
10 sq =(10-2)sq+(y-3)sq
100=8sq+ysq+3sq-6y
100=64+9+ysq-6y
ysq-6y -27=0
ysq-9y +3y-27=0
y(y-9)+3(y-9)=0
y-9=0,y+3=0
y=9,y=-3
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