find the value of y for which the distance between the point P(2,-3) and Q(10,y) is 10 unit.
plz solve this it's very urgent
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Answer:
3.33
Step-by-step explanation:
PQ(10) = (2×10) + (-3×Y)
10= 20 + -3Y
3Y= 20-10
3Y= 10
y= 10÷3
y= 3.33
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