Question

find the value of Y for which the distance between the point P (2 ,- 3 )and Q(10,y) is 10 unit

Answer 1

Answer:

Step-by-step explanation:

Let p (2,-3)

Q (10,y)

Distance at PQ = 10

Undoroot (10-2)²+(y+3)²=10

Undoroot 64+y²+9+6y =10

Squaring on both sides

64+y²+9+6y = 100

y²+6y=73+100

Y²+6y-27=0

y²+9y-3y-27=0

y(y+9)-3(y+9)=0

(y-3)(y+9)

y=3,9

Answer 2

Let x and y are two number x2+ Y2-2x.y=36 put x2+y2= 68 forme eq(1) 68-2x.y=36 -2x.y= 36-68.                            -2x.y=-32.                                                      X.y=32.                                                          2/16 answer