find the value of y for which the distances between the points p(2,-3) and q(10,y) is 10 uts
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Answer:
(10-2)2+(y+3)2=100
(8)2+y2+6y+9=100
64+y2+6y+9=100
y2+6y-27=0
y2+9y-3y-27=0
y(y+9)-3(y+9)=0
y= -9 and 3
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