Math, asked by Chitraaidlaan, 10 months ago

Find the value of y for which the expressions
(y + 6) and 3y - 12 becomes equal.​please answer

Answers

Answered by GURUSAI12345
8

Answer:

(y + 6) = 3y - 12  \\ 6 + 12 = 3y - y \\ 18 = 2y \\ 2y = 18 \\ y = 18 \div  \ 2 \\ y = 9

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