Find the value of y for which the points A(-3, 9), B(2,y) and C(4,-5) are collinear.
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Answer: For what value of P, are the points (- 3, 9), (2,p) and (4, - 5) collinear? ... x₁ = -3 x₂ = 2 x₃ = 4 y₁ = 9 y₂ = p y₃ = -5. For the points to be collinear :- ... If a+b+c=9 and ab+ bc + ca= 40, then find the value of a^2+b^2+c^2.
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Answer:
x₁ = -3
x₂ = 2
x₃ = 4
y₁ = 9
y₂ = p
y₃ = -5
For the points to be collinear :-
x₁(y₂ -y₃) + x₂(y₃ - y₂) + x₃(y₁ - y₂) = 0
-3( p - (-5)) + 2(-5 - 9) + 4( 9 - p) = 0
-3( p + 5) + 2(-14) + 4( 9 - p) = 0
-3p - 15 - 28 + 36 - 4p = 0
-7p - 7 = 0
-7p = 7
p = 7/-7
p = -1
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