find the value of Y for which the points A(-3,9),B(2,y)andC(4,-5)are collinear?
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y-9/2-(-3)= -5-y/4-2
y-9/5=-5-y/2
2(y-9)=5(-5-y)
2y-18=-25-5y
2y+5y==-25+18
7y=7
y=1
y-9/5=-5-y/2
2(y-9)=5(-5-y)
2y-18=-25-5y
2y+5y==-25+18
7y=7
y=1
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