Question

find the value of y from √3 y = y + 40​

Answer 1

Step-by-step explanation:

$\sqrt{3} y = y + 40$

$\sqrt{3} y - y = 40$

$y( \sqrt{3} - 1) = 40$

$y = \frac{40}{ \sqrt{3} - 1 }$

$y = \frac{40}{ \sqrt{3} - 1} \times \frac{ \sqrt{3} + 1 }{ \sqrt{3} + 1}$

$y = \frac{40 \times ( \sqrt{3} + 1)}{3 - 1}$

$y = 20( \sqrt{3} + 1)$

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