Question

Find the value of y , if 25²y + 15 = 640

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Answer 1

Answer:

y = ±5

Explanation:

$25 {y}^{2} + 15 = 640$

$= > 25 {y}^{2} + 15 - 640 = 0$

$= > 25 {y}^{2} - 625 = 0$

$= > {(5y)}^{2} - {25}^{2} = 0$

We know that,

${x}^{2} - {y}^{2} = (x + y)(x - y)$

${(5y)}^{2} - {25}^{2} = 0$

$= > (5y + 25)(5y - 25) = 0$

Thus,

$5y + 25 = 0$

$= > 5y = - 25$

$= > y = - 25 \div 5$

$y = - 5$

OR

$5y - 25 = 0$

$= > 5y = 25$

$= > y = 25 \div 5$

$y = 5$

So we find that,

y = 5 or y = -5

=> y = ±5

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Answer 2

Answer:

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Explanation: