Math, asked by abirbal270, 2 months ago

Find the value of y if 3^2y−5 = 27

Answers

Answered by jaswasri2006
1

 \huge \tt  {3}^{2} y = 27 + 5 = 32

 \huge  \tt 9y = 32 \implies y =  \frac{32}{9}

Answered by ashiaki
0

Answer:

3^2y−5 = 27

3^2y−5 = 3³

=> 2y-5 = 3

2y = 3+5

y = 8/2

y = 4

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