Math, asked by Amrutha23kasu, 3 months ago

find the value of Y if 7y-3(y+3-2)=17

Answers

Answered by mistumistu
1

Answer:

y=5

Step-by-step explanation:

7y-3(y+3-2)=17

= 7y-3y-9+6=17

= 4y-3=17

= 4y=17+3

= y=20/4

= y=5

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Answered by mehak4878
2

7y-3(y+3-2)=17

7y-3y-9+6 = 17

7y-3y = 17+9-6

4y = 17+3

4y = 20

y = 20/4

y = 5

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