find the value of Y if dist between points A(2,-2)and B(-1,Y)is 5
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Answer:
Step-by-step explanation:
distance=[(x2-x1)^2+(y2-y1)]^1/2
here x1=2 x2=-1 y1=-2 y2=y distance=5
5=[(-1-1)^2+(y+2)^2]^1/2
5=[4+y^2+4+4y]^1/2
squaring on both side
25=4+y^2+4+4y
y^2+4y+8-25=0
y^2+4y-17=0
apply quadratic formula now.
Hope this helps you!
Answered by
0
Answer:
2 and - 6
Step-by-step explanation:
Hope that it will help u.
If answer is wrong please let me know so that I can corrrct my mistakes.
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