Question

find the value of y if the first three terms of an AP respectively are 3y-1,3y+5and 5y+1

Answer 1

a2 -a1 =a3 - a2
3y+5-3y+1 = 5y+1-3y-5
6=2y-4
2y=10
y=5
i hope this help u

Answer 2

if it is an AP than there will be common difference between the terms
a2-a1=a3-a2
3y+5-3y+1= 5y+1-3y-5
6= 2y-4
10=2y
5=y..