Question

Find the value of y if the first three terms of an AP respectively are 3y – 1, 3y + 5 and 5y + 1.​

Answer 1

here is your answer .

The first three terms (3y—1), (3y+5) and (5y+1) are in A.P, so the common difference will be same

That is d1=d2

(3y+5)—(3y—1) = (5y+1)—(3y+5)

3y+5—3y+1=5y+1—3y—5

6=2y—4

6+4 =2y

10=2y

5=y

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