Question

Find the value of Y if the first three terms of an ap are 3 Y - 1 ,3y +5,57y+ 1

Answer 1

$3y + 5 - (3y - 1) = 57y + 1 - (3y + 5)$

$3y + 5 - 3y + 1 = 57y + 1 - 3y - 5$

$6 = 54y - 4$

$54y = 6 + 4 = 10$

$y = 10 \div 54$

$y = 0.148$