Math, asked by atec7484, 8 months ago

Find thE value of y if x=3 in given equation -3x+2y-3=0.
(A)15 (B)6 (C)7 (D)-6
Please answer this and send me the solution.

Answers

Answered by aliyakumar846
3

Step-by-step explanation:

-3X + 2y - 3 = 0

X = 3

-3(3) + 2y - 3 = 0

-9 + 2y - 3 = 0

2y = 0 + 9 + 3

2y = 12

y = 12/2

y = 6

ans : b is correct

Answered by shinurejeev2005
1

Answer:

equation:x=3

if (x+y )^2=x^2+y^2=2xy

Step-by-step explanation:

-3x+2y-3=0is also the answer gives that

-5xy+3=5-3

=2xy

3+3+2=8

the Answer is "-6"

Answer=["-6"]

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