Find the value of 'y' if y² + y / 2-3 = 0.
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Answer:
y^2+y/2 _3=0
multiply by 2
2 y^2 +y _6=0
by factorization
2 y^2 +3y _2y _6=0
y(2y+3) _ 1(2y+3)=0
(y_2)(2y+3)=0
y=2 ,y =_3/2
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