Question

find the value of y in 3y - ( y/2 + y/4 ) = 3​

Answer 1

$3y - (\frac{y}{2} + \frac{y}{4} ) = 3$

$= 3y - (\frac{2y + y}{4} ) = 3\\= 3y - \frac{3y}{4} = 3\\= \frac{12y-3y}{4} = 3\\= \frac{9y}{4} = 3\\= 9y = 3 * 4\\= y = \frac{12}{9}$