Question

find the value of y in following linear equation. 2(9y+3) =20​

Answer 1

Answer:hii,

2(9y+3)=20

18y+ 6 = 20

18y =20-6

18y= 14

y= 14/18

y= 7/9

Thank it and follow for more help

Answer 2

$\large\underline{\sf{Given - }}$

• A linear equation: 2(9y + 3) = 20

$\large\underline{\sf{To\:Find - }}$

• Value of y

$\large\underline{\sf{Solution-}}$

Basic Concept Used :-

Method of Transposition :-

Transposition is a method to isolate the variable to one side of the equation and everything else to the other side so that you can solve the equation.

Algebraic equation can be solved using the Law of equation. The Law of equations, states that whatever you do on one side of an equation, you must do on the other side as well.

We can use the following steps to find a solution using transposition method:

• Step 1) Identify the variables and constants in the given simple equation.

• Step 2) Simplify the equation in and .

• Step 3) Transpose the term on the other side to solve the equation further simplest.

• Step 4) Simplify the equation using arithmetic operation as required that is mentioned in rule 1 or rule 2 of linear equations.

• Step 5) Then the result will be the solution for the given linear equation.

Let's solve the problem now!!

$\rm :\longmapsto\:2(9y + 3) = 20$

$\rm :\longmapsto\:2 \times 9y + 2 \times 3 = 20$

$\rm :\longmapsto\:18y + 6 = 20$

$\rm :\longmapsto\:18y = 20 - 6$

$\rm :\longmapsto\:18y = 14$

$\rm :\longmapsto\:y = \dfrac{14}{18}$

$\bf\implies \:y = \dfrac{7}{9}$

$\large\underline{\sf{Verification - }}$

$\bf \: Consider \: LHS$

$\rm :\longmapsto\:2(9y + 3)$

On substituting the value of y, we get

$\rm :\longmapsto\: = \: 2\bigg( \cancel9 \times \dfrac{7}{ \cancel9} + 3 \bigg)$

$\rm :\longmapsto\: = \: 2(7 + 3)$

$\rm :\longmapsto\: = \: 2 \times 10$

$\rm :\longmapsto\: \: = \: 20$

$\rm :\longmapsto\: \: = \: \: \bf \: RHS$

Hence, Verified.