find the value of y in the equation 2y+3/10 = -5/2
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3
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Answered by
1
Answer:
AnSwEr:-
\begin{gathered}2y - 3 = \frac{3}{10} (5y - 12) \\ 10(2y - 3) = 3(5y - 12) \\ 20y - 30 = 15y - 36 \\ 20y - 15y = - 36 + 30 \\ 5y = - 6 \\ y = \frac{ - 6}{5}\end{gathered}
2y−3=
10
3
(5y−12)
10(2y−3)=3(5y−12)
20y−30=15y−36
20y−15y=−36+30
5y=−6
y=
5
−6
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