find the value of y in the figure
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46
the point where all lines intersect, consider it as O.
COE =
FOD { Vertically Opposite angles}
So, FOD = 30°
Now, AOF +
FOD +
DOB = 180°
Therefore, 90°+30°+3y = 180°
120°+3y=180°
3y = 180°-120°
3y = 120°
y = 120°/3
y = 40°
Answered by
8
Answer:-
the point where all lines intersect, consider it as O.
\large\rm { \angle}∠ COE = \large\rm { \angle}∠ FOD { Vertically Opposite angles}
So, \large\rm { \angle }∠ FOD = 30°
Now, \large\rm { \angle }∠ AOF + \large\rm { \angle }∠ FOD + \large\rm { \angle }∠ DOB = 180°
Therefore, 90°+30°+3y = 180°
120°+3y=180°
3y = 180°-120°
3y = 120°
y = 120°/3
y = 40°
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