Find the value of y in this two simultaneous linear equation , 3x + 2/y = 7 and x + 4/y = 4
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Answer :
y = 2
Solution :
Here ,
The given system of simultaneous equations is :
3x + 2/y = 7 ------(1)
x + 4/y = 4 -------(2)
Now ,
Multiplying eq-(1) by 2 , we have ;
=> 2•(3x + 2/y) = 2•7
=> 6x + 4/y = 14 ------(3)
Now ,
Subtracting eq-(2) from eq-(3) , we have ;
=> (6x + 4/y) - (x + 4/y) = 14 - 4
=> 6x + 4/y - x - 4/y = 10
=> 5x = 10
=> x = 10/5
=> x = 2
Now ,
Putting x = 2 in eq-(2) , we get ;
=> x + 4/y = 4
=> 2 + 4/y = 4
=> 4/y = 4 - 2
=> 4/y = 2
=> 4 = 2y
=> y = 4/2
=> y = 2
Hence , y = 2 .
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