find the value of y it's ncert
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use distance formula.
(10-2)^2 + y^2 +9 +6y=100
y^2 + 6y +27=0
y^2 + 9y -3y +27=0
(10-2)^2 + y^2 +9 +6y=100
y^2 + 6y +27=0
y^2 + 9y -3y +27=0
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hope this will help u
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