find the value of y please fast
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Ayaankumar:
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Answered by
1
in Δ TQR,
∠T + ∠Q + ∠R = 180° (By ∠ sum property of Δs)
40+90+x=180
x=180-130
x=50°
In ΔPSR
∠SPR+∠PSR+∠R=180
50+30+∠PSR=180
∠PSR=100°
∠PSR+∠y=180° (By linear pair)
100+∠y=180
∠y=80°
Answered by
10
Answer:
100° + ∆y = 180°
y = 80°
Hope it will be helpful ✌️
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