Question

find the value of y such that (2/-3)^-9 x (-2/3)^-3 = (-2/3)^7y+2

Answer 1

Step-by-step explanation:

(2/-3)^-9 x (-2/3)^-3 = (-2/3)^7y+2

(-2/3)^(-9-3)=(-2/3)^7y+2

(-2/3)^(-12)=(-2/3)^7y+2

-12=7y+2

7y= -14

y =-2

Answer 2

Answer:

2

Step-by-step explanation:

(2/-3)^-9×(-2/3)^-3=(-2/3)^7y+2

2/-3×-1/-1=(-2/3)^-9×(-2/3)^-3=(-2/3)^7y+2

Let's take only powers as all base are equal

-9+-3=7y+2

-12=7y+2

7y=12+2

y=14/7

y=2