Question

Find the value of ‘ y ‘ when the distance between the points (3 , a ) and ( 4 , 1 ) is
√10​

Answer 1

Answer:

distance between any two points (x1,y1),(x2,y2) is

√{(x2-x1)^2 + ( y2-y1)^2},

therefore,

√[(4-3)^2 + (1-a)^2] = √10,

=> √(1+(1-a)^2) =√10,

=> (1-a)^2 = 10-1 =9,

=> 1-a = 3,

=> a = -2.