find the value of y where 3y+10=20
Answers
Answered by
0
Answer:
y² - 3y - 10 = 0
or, y² - (5 - 2)y - 10 = 0
or, y² - 5y + 2y - 10 = 0
or, y (y - 5) + 2 (y - 5) = 0
or, (y - 5) (y + 2) = 0
Either y - 5 = 0 or, y + 2 = 0
=> y = 5, y = - 2
Therefore, the required solution be
y = 5, - 2
Step-by-step explanation:
it's helped you
Answered by
1
Answer:
10/3
Step-by-step explanation:
3y + 10 = 20
3y = 10
y = 10/3
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