Question

Find the value of y which the distance between points is P(2,-3)and Q(10,y) is 10units

Answer 1

Answer:

the formula to calculate the distance between two points (a,b) and (c,d) is given by

dist d = √(a-c)² + (b-d)²

applying it for this ques we have d=10 units

10 = √(2 - 10)² + (-3-y)²

squaring both sides

100 = (-8)² + (9 + y² + 6y)

100 = 64 +9 + y² + 6y

y² + 6y - 27 = 0

y² + 9y - 3y - 27 = 0

y(y + 9) -3(y + 9) = 0

(y-3)(y+9) = 0

y=3 or y=-9

both values of y are possible unless no other condition is specified in the question.

Step-by-step explanation:

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