Find the value of Y-X if ABCD is a rhombus in the figure given below
please answer fast
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AB||CD (Opposite sides of Rhombus are parallel)
ang CAB = ang DCA (Alternate interior angles)
Given, ang CAB = 40°
So, ang CAB = ang DCA = 40°
ang CDB + ang DCA = ang COB (Exterior Angle property)
x + 40° = y (ang CDB = x, ang DCA = 40°, ang COB = y)
40° = y-x
Hence, 40° is the answer.
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