Question

Find the value of

y² + 3(2y-2) when y = 1​

Answer 1

Answer:

1

Step-by-step explanation:

${y}^{2} + 3(2y - 2) \: when \: y = 1$

Substituting y = 1 in the given equation,

${(1)}^{2} + 3(2 \times 1 - 2)$

$1 + 3 \times 0$

$= 1$

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Answer 2

P(y)=y² + 3(2y-2)

Given that, y=1

P(1)= (1)² + 3(2×1-2)

= 1 + 3(2-2)

= 1 + 3(0)

= 1 + 0

= 1. Ans.

I hope this will help you friend.