Question

find the value of z ​

Answer 1

Step-by-step explanation:

$2 {}^{11} \div 2 {}^{5} = 2 {}^{ - 3} \times 2 {}^{2z - 1}$

$2 {}^{11 - 5} = 2 {}^{ - 3 + 2z - 1}$

now solving the exponent part as the term on both hands are equal

$11 - 5 = - 3 + 2z - 1$

$6 = - 4 + 2z$

$6 + 4 = 2z$

$10 \div 2 = z$

$5 = z$